Question

F(x) = 4/3(x + 3)2, what is the value of f(–8)?

Answer 1

Explanation:

Assuming f(x) = 4/3(x + 3)2 is meant to be written as:

`f(x) = (4)/(3)(x+3)^(2)`

for f(-8), you plug in -8 wherever there is an x in f(x)

`f(-8) = (4)/(3)((-8)+3)^(2)\\\\f(-8) = (4)/(3)(-5)^(2)\\\\f(-8) = (4)/(3)25\\\\f(-8) = (100)/(3)\\\\f(-8) = 33(1)/(3)\\\\`

`f(-8)` ≈ 33.3333333...