Answer: 1/10th of its weight on Earth.
Explanation: Let's assume that the weight of the object on Earth is W, and the gravitational acceleration on Earth is g. We know that weight is given by the formula:
W = m * g where m is the mass
If the gravitational attraction on another planet is 1/10th of Earth's pull, then the gravitational acceleration on that planet will be:
g' = g/10
Using the same formula for weight, the weight of the object on the new planet will be:
W' = m * g'
Substituting the value of g' in the equation above, we get:
W' = m * (g/10)
W' = (m/10) * g
Therefore, the weight of the object on the new planet will be 1/10th of its weight on Earth.
W' = (100/10) N = 10 N
So, the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10th of Earth's pull would be 1/10th of its weight on Earth.