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What is the gravitational potential energy (GPE) of the 2 kg bowling ball as it sits on top of the building 40 meters high?

Use this formula: GPE=m(9.8m/s²)h

Potential Energy (GPE) is measured in Joules (J)
Mass (m) is measured in kilograms (kg)
Height (h) is measured in meters (m)/

A) GPE = 9.8 x 40 = 392 J
B) GPE = 2 x 40 = 80 J
C) GPE = 40 / 2= 20 J
D) GPE = 2 x 9.8 x 40 = 784 J

User Montreal
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2 Answers

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2 x 9.8 x 40 = 784 J
User Sammyukavi
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Answer:

To find the gravitational potential energy (GPE) of the 2 kg bowling ball as it sits on top of the building 40 meters high.

Use the GPE equation: GPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object. In this case, m = 2 kg, g = 9.8 m/s2, and h = 40 m, so GPE = 2 x 9.8 x 40 = 784 J.

User Yun CHEN
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