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Find the perimeter of a rectangle if the length is 4x+2 and the width is 7y-7

User Andoctorey
by
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2 Answers

4 votes

Answer:

14y+8x-10

Explanation:

(4x+2)+(7y-7)+(4x+2)+(7y-7)=

4x+2+7y-7+4x+2+7y-7=

8x+4+14y-14=

14y+8x-10

( hopes it helps!)

User Sequoya
by
7.9k points
7 votes

Answer:

The perimeter of a rectangle is the total length of all four sides.

To find the perimeter of a rectangle with length 4x+2 and width 7y-7, we use the formula P=2L+2W where L is the length and W is the width.

Therefore, P=2(4x+2)+2(7y-7)=8x+14y-10. Thus, the perimeter of this rectangle is 8x+14y-10.

Explanation:

Identify the given values of the rectangle: the length is 4x+2 and the width is 7y-7.

Use the formula for perimeter to calculate the perimeter: P = 2(L + W)

Substitute the given values into the equation: P = 2(4x+2 + 7y-7)

Simplify the equation: P = 2(4x + 7y - 5)

Solve for the perimeter: P = 8x + 14y - 10 Therefore, the perimeter of the rectangle is equal to 8x + 14y - 10.

User Charisis
by
8.4k points