Final answer:
To determine the milligrams of CCl₄ produced when 325 milligrams of CS₂ reacts with Cl₂, we need to use the balanced chemical equation and stoichiometry. Using the molar mass of CS₂ (76.15 g/mol) and the given mass of 325 milligrams, we can calculate the number of moles of CS₂. Then, using the stoichiometry, we can determine the number of moles of Cl₂ required for the reaction. Finally, using the molar mass of CCl₄ (153.82 g/mol), we can convert moles of Cl₂ to milligrams of CCl₄.
Step-by-step explanation:
To determine the milligrams of CCl₄ produced when 325 milligrams of CS₂ reacts with Cl₂, we need to use the balanced chemical equation and stoichiometry. From the equation: CS₂(g) + 3 Cl₂(g) → CCl₄(l) + S₂Cl₂(s), we can see that 1 mole of CS₂ reacts with 3 moles of Cl₂ to produce 1 mole of CCl₄. We can calculate the number of moles of Cl₂ present in 325 milligrams of CS₂ and then use the stoichiometry to find the corresponding mass of CCl₄.
Using the molar mass of CS₂ (76.15 g/mol) and the given mass of 325 milligrams, we can calculate the number of moles of CS₂. Then, using the stoichiometry, we can determine the number of moles of Cl₂ required for the reaction. Finally, using the molar mass of CCl₄ (153.82 g/mol), we can convert moles of Cl₂ to milligrams of CCl₄. The calculation would be as follows:
(325 mg CS₂) / (76.15 g/mol CS₂) imes (3 mol Cl₂) / (1 mol CS₂) imes (153.82 g/mol CCl₄) = X mg CCl₄
Substituting the values into the calculation, we can find the milligrams of CCl₄ produced.