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A 1.6kg ball traveling 4.6m/s horizontally landed in a 22kg wheeled cart that began at rest. What was the final velocity of the system?

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A 1.6kg ball traveling 4.6m/s horizontally landed in a 22kg wheeled cart that began-example-1
User Kolodach
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Answer:

Step-by-step explanation:

The equation of motion states that the change in velocity of an object is proportional to the force acting upon it, divided by its mass.

Given:

m₁ = 1.6 kg

v₁ = 4.6 m/s

m₂ = 22 kg

v₂ = 0

The force acting on the system is equal to the mass of the ball multiplied by its initial velocity, so F = m₁v₁ = (1.6 kg)(4.6 m/s) = 7.36 kgm/s.

Using the equation of motion:

Δv = F/m

v₂ = F/m₂ = (7.36 kgm/s)/(22 kg) = 0.335 m/s

User Hui Zheng
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