Answer:
Step-by-step explanation:
To calculate the mass of Li3PO4 needed to prepare 500 mL of a solution having a lithium ion concentration of 0.175 M is to use the density of the solution. First, we need to calculate the density of the solution. The density of the solution is equal to the mass of Li3PO4 needed divided by its volume in Liters. We know that the mass of Li3PO4 needed is 8.94 g and the volume of the solution is 500 mL, which is equivalent to 0.5 L. Therefore, the density of the solution is 8.94 g/0.5 L = 17.88 g/L. We can then calculate the mass of Li3PO4 needed by multiplying the density of the solution by the volume of the solution. The mass of Li3PO4 needed is therefore 17.88 g/L x 0.5 L = 8.94 g