Question

A man drags a bin with an effective constant horizontal force of 100N on a horizontal surface. If the bin starts from rest and moves a distance of 100m in 10s with the constant horizontal force exerted to overcome a constant kinetic friction of 20N, what is the mass of the bin

Answer 1

answer is 8kg

total force is 100-20= 80N

according to Newton second law force is equal to change in momentum velocity =100/10 =10 10m/s Mv=80 M=80/10 8kg

Answer 2

Below

Step-by-step explanation:

F of kinetic friction = 20 N

so NET force moving the bin = 100 -20 = 80 N

Average velocity = 100 m / 10 s = 10 m/s

Find final velovity: (vf - 0)m/s / 2 = 10 m/s

v f = 20 m/s

acceleration = change in v / change in t = 20 m/s / 10 s = 2 m/s^2

F= ma

80 N = m *2 m/s^2

40 kg = mass