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If -9x-6y=3 and 2x+7y=6 are true equations what would be the value of 11x+13y

User Shxfee
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1 Answer

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To solve for the value of 11x + 13y, we need to first solve the system of equations:

-9x - 6y = 3 ...(1)

2x + 7y = 6 ...(2)

Multiplying equation (1) by 2, we get:

-18x - 12y = 6 ...(3)

Adding equation (2) and (3), we get:

-16x - 5y = 12

Multiplying this equation by -2, we get:

32x + 10y = -24

Adding this to the original equation (2), we get:

33x = -18

Therefore, x = -18/33

Substituting this value of x in equation (2), we get:

2(-18/33) + 7y = 6

Simplifying, we get:

7y = (396/33) - (198/33) = (198/33)

Therefore, y = (198/33) / 7 = 6/11

Finally, substituting the values of x and y, we get:

11x + 13y = 11(-18/33) + 13(6/11) = -6

So, the value of 11x + 13y is -6.

Brainliests Answer pleasee

User Tmslnz
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