Question

35.2 J of heat is

applied to 16.0 g
of a substance.
Temp rises by 7.2
K. Specific Heat?

Answer 1

The specific heat : c = 0.306 J/g K

Further explanation

Given

Heat = 35.2 J

Mass = 16 g

Temperature difference : 7.2 K =

Required

The specific heat

Solution

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Input the value :

c = Q / m.∆T

c = 35.2 / 16 x 7.2

c = 0.306 J/g K