Answer:
The kinetic energy of the bus can be expressed as:
K.E. = (1/2) * m * v^2
where K.E. is the kinetic energy, m is the mass of the bus, and v is the velocity.
Substituting the given values, we have:
493900 = (1/2) * 5040 * v^2
Simplifying and solving for v, we get:
v^2 = (2 * 493900) / 5040
v^2 = 195.6349
v = √195.6349
v ≈ 13.988 m/s (rounded to three significant figures)
Therefore, the velocity of the bus is approximately 13.988 m/s.
Step-by-step explanation: