Answer:
-1, 0, 1, 6
Explanation:
You want the real zeros of the function g(x) = -3x(x -6)(x² -1).
Special product
The difference of squares is factored as the product of a sum and difference:
a² -b² = (a +b)(a -b)
Factored form
Then the fully-factored function can be written as ...
g(x) = -3x(x -6)(x +1)(x -1)
The zeros are the values of x that make the factors zero:
-3x = 0 ⇒ x = 0
x -6 = 0 ⇒ x = 6
x +1 = 0 ⇒ x = -1
x -1 = 0 ⇒ x = 1
The real zeros of g(x) are -1, 0, 1, 6.