Answer:
Explanation:
First, let's calculate the total water required per day for all the calves:
82 calves x 5 gal/head/day = 410 gallons/day
Next, we can calculate the volume of water that each tank can hold:
4' x 2' x 2' oval tank: (4 x 2 x 2) + (π x 2² x 0.5) = 16 + 6.28 = 22.28 cubic feet = 166.5 gallons
6' x 2' x 2' oval tank: (6 x 2 x 2) + (π x 2² x 0.5) = 24 + 6.28 = 30.28 cubic feet = 227 gallons
8' x 3' x 2' oval tank: (8 x 3 x 2) + (π x 3² x 0.5) = 48 + 14.14 = 62.14 cubic feet = 466 gallons
8' diameter x 2' tall round tank: (π x 4² x 2) / 3 = 100.53 cubic feet = 754 gallons
To determine which tank(s) to purchase, we need to make sure that the total volume of water they can hold is at least 410 gallons.
Option 1 (4' x 2' x 2' oval tank) holds 166.5 gallons, so we would need to purchase at least 3 of them to meet the total water requirement (3 x 166.5 = 499.5 gallons). This would cost $420.
Option 2 (6' x 2' x 2' oval tank) holds 227 gallons, so we would need to purchase at least 2 of them to meet the total water requirement (2 x 227 = 454 gallons). This would cost $420.
Option 3 (8' x 3' x 2' oval tank) holds 466 gallons, so one tank would be enough to meet the total water requirement. This would cost $390.
Option 4 (8' diameter x 2' tall round tank) holds 754 gallons, which is more than enough to meet the total water requirement. However, it is the most expensive option at $500.
Based on these calculations, the best option would be the 8' x 3' x 2' oval tank, which can hold enough water for all the calves and is also the most cost-effective option.