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What is an equation of the line that passes through the points (4,0) and (3, 1)

User Einclude
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1 Answer

4 votes

Answer:

y = -x + 4

Explanation:

The equation is y = mx + b

m = the slope

b = y-intercept

Slope = rise/run or (y2 - y1) / (x2 - x1)

Points (4,0) and (3, 1)

We see the y increase by 1 and the x decrease by 1, so the slope is

m = -1

Y-intercept is located at (0,4)

So, our equation is y = -x + 4

User Pathdependent
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