Final answer:
The formula for lead(II) bromide is PbBr2, which is an insoluble compound forming a precipitate in reactions with bromide solutions according to the solubility rules.
Step-by-step explanation:
The student asked for the formula for lead(II) bromite. However, there is a little confusion here as "bromite" is not a recognized ion. What we probably are looking for is the compound formed from lead(II) or Pb2+ and bromide ions, Br-. The compound that matches this description is lead(II) bromide, with the formula PbBr2.
Lead(II) bromide is the result of a reaction between lead ions and bromide ions. For example, when solutions of cesium bromide and lead (II) nitrate are mixed, a reaction occurs where the potential precipitate is lead(II) bromide, according to solubility rules. Because lead(II) bromide is insoluble in water, it forms a precipitate, while cesium and nitrate ions act as spectator ions in the solution.