Question

How many solution does the equation 6z+1=2(3z-1) have

Answer 1

To find out the number of solutions in this equation, we begin by simplifying.

6z + 1 = 6z - 2

Now, we subtract 6z on both sides to isolate the variable:

(6z - 6z) + 1 = (6z - 6z) - 2

1 = -2

Because 1 ≠ -2, this equation has no solutions. 1 will never be equivalent to -2 without an inputted variable.