Question

8. Objects near Earth's surface fall with an acceleration of 9.81m/s². If you dropped a rock from a cliff

over a river, how fast would the rock be falling 4.1s after you dropped it?

Answer 1

Explanation:

We can use the formula for the distance fallen by a falling object, which is:

d = 1/2 * a * t^2

where d is the distance fallen, a is the acceleration due to gravity, and t is the time in seconds.

We can use this formula to find the distance the rock has fallen after 4.1 seconds:

d = 1/2 * 9.81 m/s^2 * (4.1 s)^2 = 84.88 meters

Next, we can use the formula for the velocity of a falling object, which is:

v = a * t

where v is the velocity and a and t are the acceleration due to gravity and time, respectively.

We can use this formula to find the velocity of the rock at the end of the 4.1 seconds:

v = 9.81 m/s^2 * 4.1 s = 40.221 m/s

Therefore, the rock would be falling at a velocity of 40.221 m/s after 4.1 seconds.