Question

Stoichiometry

2Al+3H2SO4 > Al2(SO4)3 + 3H2
How many grams of aluminum sulfate would be formed if 250 g H2SO4 completely reacted with aluminum

Answer 1

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

3mol H2SO4 produce 1 mol Al2(SO4)3\

Molar mass H2SO4 = 98 g/mol

Mass 3 mol H2SO4 = 98 g/mol * 3 mol = 294 g

Molar mass Al2(SO4)3 = 342 g/mol

294 g H2SO4 produce 342 g Al2(SO4)3

250 g H2SO4 will produce 250 g / 294 g * 342 g Al2(SO4)3 = 291 g Al2(SO4)3