Question

M for which - x² +8x+m=0 will have two positive roots.​

Answer 1

`m=-16`

Explanation:

`-x^(2) +8x+m=0`

Reverse the signs:

`x^(2) -8x-m=0`

if m = -16

`x^(2) -8x-(-16)=0\\x^(2) -8x+16=0`

Factoring:

`(x-4)(x-4)=0`

When the factors are cleared, we are left with two positive roots (+4)

Hope this helps.

Answer 2

Answer: m=-8

Explanation:

Alright so take m over to the other side and the equation becomes:

-x^2 + 8x + 0 = -m

then use the quadratic formula to find out the 2 values for -m

those are: 8, 0

0 cant be it because it will give us 8 and 0, 0 cant be identified as a positive value so we are only left with 8 to choose.

8 = -m

m= -8