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A motor that is capable of producing a maximum power output of 3.0 kilowatts is used to lift a 100 kilogram load of bricks a distance of 20 meters. How long will it take the motor to lift this load if it is working at maximum power?

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Answer:

Step-by-step explanation:

To solve this problem, we need to use the equation for work:

Work = Force × Distance

where Force is the weight of the load (mass × acceleration due to gravity).

Given that the load is 100 kilograms, its weight is:

Force = mass × acceleration due to gravity = 100 kg × 9.81 m/s^2 = 981 N

The work done in lifting the load a distance of 20 meters is:

Work = Force × Distance = 981 N × 20 m = 19,620 J

The time taken to do this work depends on the power output of the motor, which is given as 3.0 kilowatts (3,000 watts).

Power = Work / Time

Rearranging this equation to solve for time, we get:

Time = Work / Power

Substituting the values we have, we get:

Time = 19,620 J / 3,000 W

Time = 6.54 seconds (rounded to two decimal places)

Therefore, it will take the motor approximately 6.54 seconds to lift the 100 kilogram load of bricks a distance of 20 meters at maximum power.

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