Question

Factorize (9+x)^2 -(4 - x)^2​

Answer 1

11[2x+3]

Explanation:

[9+x]^2 - [4-x]^2
= x^2+2[9][x]+[9]^2 - {x^2-2[4][x]+[4]^2}
= x^2+14x+49 - {x^2-8x+16}
= x^2+14x+49 - x^2+8x-16
= 22x+33
= 11[2x+3]

Answer 2

The answer is : 13(5 + 2x)





(9+×)2-(4-×2
Factor the expression using
a2-b2 = (a+b)(a- b)
((9 + x) + (4 - x)) ((9 + x) - (4 - x))

Remove the parentheses
(9 + × +4-X)(9+x-4 + x)

(9 + × + 4 - x)(9 + × - 4 + x)

13(5 + 2x)

So the answer is ::: 13(5 + 2x)