Answer:
C4H8O2
Step-by-step explanation:
Step 1: Calculating the mass of carbon, hydrogen, and oxygen in 0.956 g dioxane.
C = 1.91 g CO 2 × (1 mol CO2/ 44 g CO2) × ( 1 mol C / 1 mol CO2 ) × ( 12 g C / 1 mol C )
= 0.521 g
H = 0.782 g H2O × (1 mol H2O/ 18 g H2O) × ( 2 mol H / 1 mol H2O ) × ( 1 g H / 1 mol H )
= 0.087 g
O = 0.956 dioxane - 0.521 g C -0.087g H
= 0.348g
Step 2: Using the data from step 1 above, calculating the empirical formula of dioxane.
C = 0.521 g × (1 mol C/ 12 g C)
= 0.043 mol
H = 0.087 g × (1 mol H/ 1.008 g H)
= 0.087 mol
O = 0.348g × (1 mol O / 12.01 g O)
= 0.022 mol
The empirical formula is: C0.043H0.087O0.022
Step 3 : Calculating the molecular weight of dioxane.
Molecular weight = grams / mole
= 0.532 g dioxane / 0.00604 mol dioxane
= 88.1 g / mol
The empirical formula weight is 2(12.0) + 4(1.01) + 16.0 = 44.0. The molecular weight is 88.08. The ratio of molecular weight to empirical weight is:
Molecular weight / Empirical weight = 88/44 = 2
Therefore the molecular formula is: C4H8O2.