Answer:
Explanation:
Let's denote the cost of an adult ticket by 'a' and the cost of a child ticket by 'c'. We can set up a system of two equations based on the given information:
Equation 1: 5a + 3c = 99
Equation 2: 8a + 6c = 168
We can solve for 'a' and 'c' by using elimination or substitution. Here, we'll use elimination:
Multiplying Equation 1 by 2, we get:
10a + 6c = 198
Subtracting Equation 2 from this, we get:
(10a + 6c) - (8a + 6c) = 198 - 168
Simplifying, we get:
2a = 30
Dividing both sides by 2, we get:
a = 15
Substituting this value of 'a' into Equation 1, we get:
5(15) + 3c = 99
Simplifying, we get:
75 + 3c = 99
Subtracting 75 from both sides, we get:
3c = 24
Dividing both sides by 3, we get:
c = 8
Therefore, an adult ticket costs £15 and a child ticket costs £8.