Question

The electric field in the copper wire of a household circuit is oriented along

the wire, so that it pushes electrons through the circuit. (In alternating current,
the direction of this electric field reverses 120 times a second.) A typical value for
the field strength is 0.00850 N/C. The charge of a mobile electron in the wire is
19
1.60×10 C. What is the magnitude of the force that the field exerts on the
electron?

Answer 1

1.36×10^-21 N.

Step-by-step explanation:

The magnitude of the force that the electric field exerts on the electron can be calculated using the formula:

F = qE

where F is the force, q is the charge of the electron, and E is the electric field strength.

Substituting the given values, we get:

F = (1.60×10^-19 C) × (0.00850 N/C)

F = 1.36×10^((-21) N

Therefore, the magnitude of the force that the electric field exerts on the electron is 1.36×10^-21 N.