Question

Calculate the number of grams of 02, produced when 43 grams of potassium chlorate decomposes.

2KClO3=3O2+2KCl

Answer 1

Mass O2 = = 16.832 g

Further explanation

Given

43 grams of potassium chlorate

Required

Mass of O2

Solution

Reaction

2KClO3 ⇒3O2 + 2KCl

Mol KClO3 :

= mass : MW

= 43 g : 122,55 g/mol

= 0.3509

From the equation, mol O2 :

= 3/2 x moles KClO3

= 3/2 x 0.3509

= 0.526

Mass O2 :

= 0.526 x 32 g/mol

= 16.832 g