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Find the value of x round to the nearest tenth

Find the value of x round to the nearest tenth-example-1

1 Answer

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Answer:

x ≈ 5.7

Explanation:

For this problem, we should use the Pythagorean Theorem. This is an important theorem used to find a missing side of a right triangle.

Theorem:


a^(2) +b^(2) =c^(2) \\(Short \ Side)^(2) + (Long \ Side)^(2) = (Hypotenuse)^(2)

We are given 2 values:

  • The long leg equals 7.
  • The hypotenuse equals 9.

Substitute:


x^(2) + 7^(2) = 9^(2)

Subtract:


9^(2) - 7^(2) =x^(2)


32=x^(2)

Square root to cancel out the exponent:


√(x^2) = √(32)

Evaluate:

x ≈ 5.7.

User DoneForAiur
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