Question

3 moles of Mg(OH)2 are used to make a 0.5 L solution. What is the molarity of this solution?

Answer 1

molarity = 6.0 mol/L

Step-by-step explanation:

To make an aqueous solution of Mg(OH)₂, the concentration will be calculated by: concentration (c) (or molarity) = number of moles present (n) ÷ volume needed (V) (in litres)

∴ c(SrF₂) = n/V = 3/0.5L = 6.0 mol/L