Answer:
Molarity = 0.2222 mol/L
Step-by-step explanation:
To make an aqueous solution of SrF₂ (Strontium has an ionic charge of 2+, being a group 2 element, and fluorine has an ionic charge of 1-, being a noble gas), the concentration will be calculated by: concentration (c) (or molarity) = number of moles present (n) ÷ volume needed (V) (in litres)
∴ c(SrF₂) = n/V = 2/9L = 0.2222 mol/L