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2 moles of SrF are used to make a 9 liter solution. What is the molarity of this solution?

User Rcanpahali
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1 Answer

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Answer:

Molarity = 0.2222 mol/L

Step-by-step explanation:

To make an aqueous solution of SrF₂ (Strontium has an ionic charge of 2+, being a group 2 element, and fluorine has an ionic charge of 1-, being a noble gas), the concentration will be calculated by: concentration (c) (or molarity) = number of moles present (n) ÷ volume needed (V) (in litres)

∴ c(SrF₂) = n/V = 2/9L = 0.2222 mol/L

User Svbaker
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