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Can you please help me with this question?

Can you please help me with this question?-example-1
User Jryl
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1 Answer

6 votes

Answer:

Code Value in pF Value in μF

472 4700 pF 0.0047 μF

334 330,000 pF 0.33 μF

683 68,000 pF 0.068 μF

Step-by-step explanation:

A capacitor code has 3 digits. The first two digits indicate the capacitance in and the last digit is the multiplier. The entire sequence gives the capacitor value in pF

Also 1 pF = 10⁻⁶ μF so to convert from pF to μF divide by 10⁶ which is a million

Code 472

Code 472 = 47 x 10²= 4700 pF

So 4700 pF = 4700 x 10⁻⁶
= 4700/10⁶
= 4700/1,000,000
= 0.0047 μF

Code 334

Value in pF = 33 x 10⁴ = 330,000 pF

Value in μF = 330,000 x 10⁻⁶ μF = 0.33 μF

Code 683
Value in pF = 68 x 10³ = 68,000 pF

Value in μF = 68,000 x 10⁻6 = 0.068 μF

User TheOnlyXan
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