Question

Treat the box as an object upon which the external force is exerted over a displacement d=5m, while velocity remains constant, what is the total work done by the box by the net force?

Answer 1

The total work done by the net force is equal to the product of the net force and the displacement, so the total work done by the box is equal to the net force multiplied by 5m, or F•d = 5F.