Answer:
the width of the label is 11.4 inches (rounded to one decimal place).
Explanation:
Let's call the width of the label "w". According to the problem, the ratio of height to width is 5 to 19, which can be written as:
height/width = 5/19
We are given that the height of the label is 3 inches, so we can substitute this into the equation:
3/w = 5/19
To solve for w, we can cross-multiply to get:
3 × 19 = 5 × w
57 = 5w
w = 57/5
So the width of the label is 11.4 inches (rounded to one decimal place).