Answer:
Step-by-step explanation:
To solve this problem, we need to use the Avogadro's number to convert the given number of molecules to moles, and then use the molar mass of CCl4 to convert to grams.
1 mole of any substance contains Avogadro's number of particles, which is approximately 6.02 × 10^23 particles.
The molar mass of CCl4 is 12.01 + 4(35.45) = 153.82 g/mol.
So, we have:
4.63 × 10^23 molecules of CCl4 = (4.63 × 10^23) / (6.02 × 10^23) moles of CCl4
= 0.769 moles of CCl4
Then, we can use the molar mass of CCl4 to convert to grams:
0.769 moles of CCl4 × 153.82 g/mol = 118.3 g
Therefore, 4.63x10^23 molecules of CCl4 is equivalent to 118.3 grams of CCl4.