Please help me. I am lost. Rewrite 2sinx-cos^2x-2 using only one trig function.

asked Sep 7, 2024 84.7k views

2 votes

Please help me. I am lost.
Rewrite 2sinx-cos^2x-2 using only one trig function.

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Answer:(sinx+1)^2-4

Explanation:

2sinx-cos^2x-2 =2sinx-(1-sin^2x)-2=2sinx-1+sin^2x-2=2sinx+sin^2x-3=(sinx+1)^2-4

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