Question

Answers? drop them. i need them baddddd

Answer 1

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-3}-\stackrel{y1}{(-7)}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{(-4)}}} \implies \cfrac{-3 +7}{4 +4} \implies \cfrac{ 4 }{ 8 } \implies \cfrac{ 1 }{ 2 }`

`\begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{ \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{(-4)}) \implies y +7 = \cfrac{ 1 }{ 2 } ( x +4) \\\\\\ y+7=\cfrac{ 1 }{ 2 }x+2\implies {\Large \begin{array}{llll} y=\cfrac{ 1 }{ 2 }x-5 \end{array}}`