Question

(a) Propyne reacts with hydrogen as follows:

C3H4(g) + 2H2(g) → C3H8(g) HӨ = –287 kJ

Calculate the standard entropy change of this reaction, given the following additional
information:

SӨ of H2(g) = 131 J K–1 mol–1


(b) Calculate the standard free energy change at 298 K, GӨ, for the reaction in part
your answer and relevant information from part (d). If you did not obtain an answer to
part (a), use SӨ = –360 J K–1 (this is not the correct value).

Answer 1

Answer: C3H4(g) + 2H2(g) → C3H8(g) HӨ = –287 kJ

Explanation:

SӨ of H2(g) = 131 J K–1 mol–1