Question

Jenny had 30 minutes to do a three problem quiz.She spent 9 9/10 on question A and 4 3/5 minutes on question B.How much time did she have left for question C?

Answer 1

15
`(1)/(2)`

Explanation:

30 - (9
`(9)/(10)` + 4
`(3)/(5))` I need a common denominator. I could use lots of different numbers, but 10 would be the easiest.

`(3)/(5)` x
`(2)/(2)` =
`(6)/(10)`

30 - (9
`(9)/(10)` + 4
`(6)/(10)`)

30 - 13
`(15)/(10)`

13
`(15)/(10)` is the same as 13 +
`(10)/(10)` +
`(5)/(10)` = 13 + 1 +
`(5)/(10)` = 14
`(5)/(10)`

30 - 14
`(5)/(10)`

29
`(10)/(10)` - 14
`(5)/(10)` = 15
`(5)/(10)`

`(5)/(10)` ÷
`(5)/(5)` =
`(1)/(2)`

15
`(1)/(2)`

I used that I know any number over itself is equal to 1. For example,
`(10)/(10)` is the same as 1.

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