Question

and produced to meet QS at X. Prove that QX SX. २) चित्रमा दुईओटा वृत्तहरू P र Q मा काटिएका छन् । सानो वृत्तको केन्द्रबिन्दु ठूलो वृत्तको परिधिमा पर्दछ र RO लाई जोडेर लम्ब्याउँदा QS को X मा भेट हुन्छ । RQ= RS हुन्छ भनी प्रमाणित गर्नुहोस् । In the figure, two circles intersect at P and Q. O is the centre of the smaller circle which lies on the circumference of the larger circle and RO is joined and produced to meet QS at X. Prove that RQ = RS. R P ● IS X​

Answer 1

In order to prove that RQ = RS, we need to consider the properties of a circle. Firstly, we know that the radius (RQ) of a circle is equal to its circumference (RS), and the circumference of a circle is related to its diameter by the formula 2πr = C, where r is the radius and C is the circumference.

Therefore, since QS is a diameter of the larger circle and RO is the radius of the smaller one, we can use the formula to calculate the circumference of the larger circle using the radius of the smaller one. If we substitute r with RO and C with QS, we get: 2πRO = QS. We can then simplify this to get RQ = RS.