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A rod of initial length 20.0m at a temperature of 25°C is heated to 80°C. Calculate the increase in length of the rod if it's linear expansivity is 4.0*10^-5 k^-1​

User Mcdave
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1 Answer

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Answer:

The increase in length of a material due to temperature change is given by the formula:

ΔL = αLΔT

where:

ΔL is the change in length

α is the coefficient of linear thermal expansion of the material

L is the original length of the material

ΔT is the change in temperature

In this case, the rod has an original length of L = 20.0 m and a coefficient of linear thermal expansion of α = 4.0 × 10^-5 K^-1. The temperature change is ΔT = 80°C - 25°C = 55°C.

Plugging these values into the formula, we get:

ΔL = αLΔT

ΔL = (4.0 × 10^-5 K^-1)(20.0 m)(55°C)

ΔL = 0.044 m

Therefore, the increase in length of the rod is 0.044 m or 4.4 cm.

User Lidi Zheng
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