Question

A brass rod at 10.0m melts at 41°C. What will be it's new length at 30°C. Linear expansivity of brass is 2.0*10 raised to the power of -5 per kelvin​

Answer 1

Step-by-step explanation:

To solve this problem, we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the linear expansivity coefficient of brass, L is the original length of the brass rod, and ΔT is the change in temperature.

Given:

α = 2.0 × 10^-5 K^-1 (linear expansivity coefficient of brass)

L = 10.0 m (original length of the brass rod)

ΔT = 41°C - 30°C = 11°C (change in temperature)

Using the formula:

ΔL = αLΔT

ΔL = (2.0 × 10^-5 K^-1) × (10.0 m) × (11°C)

ΔL = 0.0022 m

Therefore, the new length of the brass rod at 30°C will be:

L' = L + ΔL

L' = 10.0 m + 0.0022 m

L' = 10.0022 m

So, the new length of the brass rod at 30°C will be approximately 10.0022 meters.