Question

The floor of a rectangular hall is of length 9cm and width 4cm. How many tiles of 20cm by 30cm can be used to cove the floor completely?

Answer 1

Answer: 600 tiles

Explanation:

Area of the hall (assuming a typo and is metres,) = 900x400

= 360000cm2

Area of the tiles = 600cm2

Amounts of tiles able to be used = 360000/600

= 600 tiles.

Answer 2

Explanation:

I think 9cm and 4 cm are the lengths of the tile. so assuming that

First, we need to calculate the area of the floor in square centimeters:

Area of the floor = length x width

Area of the floor = 20cm x 30cm

Area of the floor = 600 square centimeters

Next, we need to calculate the area of one tile in square centimeters:

Area of one tile = length of tile x width of the tile

Area of one tile = 9cm x 4cm

Area of one tile = 36 square centimeters

To find the number of tiles needed to cover the floor completely, we need to divide the area of the floor by the area of one tile:

Number of tiles needed = Area of the floor / Area of one tile

Number of tiles needed = 600 square centimeters / 36 square centimeters

Number of tiles needed = 16.67

Since we can't have a fraction of a tile, we round up to the nearest whole number. Therefore, we need 17 tiles of size 9cm by 4cm to cover the floor completely.