Answer:
To solve the equation x^2 + 4x = 56, we can start by rearranging it to the standard quadratic form:
x^2 + 4x - 56 = 0
Next, we can use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
In this case, a = 1, b = 4, and c = -56, so we have:
x = (-4 ± sqrt(4^2 - 4(1)(-56))) / 2(1)
x = (-4 ± sqrt(240)) / 2
x = (-4 ± 15.49) / 2
x = (-4 + 15.49) / 2 or x = (-4 - 15.49) / 2
x = 5.745 or x = -9.745
Therefore, the solutions to the equation x^2 + 4x = 56 correct to one decimal place are x = 5.7 and x = -9.7