Question

If the effort is 250N and effort distance is Im and load distance to 25 cm. Calculated 11 load​

Answer 1

`the \: load \: is \: 1000n`

1000N

Step-by-step explanation:

Greetings!!!

Firstly, recall about simple machine

• L.F× L.D ≈E.F×E.D.

Where, L.F.- Load Force

• L.D.- Load Distance
• E.F.- Effort Force
• E D.- Effort Distance

Substitute known variables into the equation

• L.F.×0.25m= 250N× 1m

change the cm into m.

`0.25m (l.f) = 250n.m`

Divide both sides by 0.25m

`(0.25m(l.f))/(0.25m) = (250n.m)/(0.25m)`

Cancel out the meter by meter and solve for L.F.

• L.F.= 1000N

If you have any questions tag me on comments

Hope it helps!!!