119k views
3 votes
How many grams of oxygen gas are required to react with 0.25 moles of iron?

User Haplo
by
7.4k points

1 Answer

7 votes

Answer:

Step-by-step explanation:

The balanced chemical equation for the reaction between iron (Fe) and oxygen (O2) is:

4 Fe + 3 O2 → 2 Fe2O3

This means that for every 3 moles of oxygen gas consumed, 4 moles of iron react to form 2 moles of iron oxide.

We can use this ratio to determine how many moles of oxygen gas are required to react with 0.25 moles of iron:

3 moles O2 : 4 moles Fe = x moles O2 : 0.25 moles Fe

x = (0.25 moles Fe x 3 moles O2) / 4 moles Fe

x = 0.1875 moles O2

So 0.1875 moles of oxygen gas are required to react with 0.25 moles of iron.

To convert moles of oxygen to grams, we need to use the molar mass of oxygen, which is 16.00 g/mol. Therefore, the mass of oxygen required is:

0.1875 moles O2 x 16.00 g/mol = 3.00 g of O2

So 3.00 grams of oxygen gas are required to react with 0.25 moles of iron.

User Magicismight
by
7.5k points