90.4k views
4 votes
Evaluate f(6) and f(6.1) and use the results to approximate f '(6).

f(x)= x(9-x)
(Round answer to one decimal place)

User Berker
by
8.5k points

1 Answer

4 votes

Answer: To evaluate f(6), we substitute 6 for x in the expression for f(x):

f(6) = 6(9-6) = 18

To evaluate f(6.1), we substitute 6.1 for x in the expression for f(x):

f(6.1) = 6.1(9-6.1) = 16.99

To approximate f '(6), we can use the formula for the derivative of a function:

f '(x) = lim(h→0) [f(x+h) - f(x)]/h

We can use the values we just calculated to estimate the value of f '(6) by setting x = 6 and h = 0.1:

f '(6) ≈ [f(6.1) - f(6)]/0.1

f '(6) ≈ (16.99 - 18)/0.1

f '(6) ≈ -1.01/0.1

f '(6) ≈ -10.1

Therefore, we can approximate f '(6) as -10.1, rounded to one decimal place.

Explanation:

User Alejandro Condori
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories