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If four is added to two times a number, the result is fifty-nine less than the square of the number. Find all such numbers.

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1 Answer

3 votes

Answer:

9 and -7

Explanation:

First, translate the word problem into an algebraic equation.

Let x represent the number to be determined

4 added to 2 times a number ==> 2x + 4

59 less than square of number ==> x² - 59

Equating the two we get
x² - 59 = 2x + 4

Move the term on the right to the left; the signs will change for each term
x² - 59 - 2x - 4 = 0

x² - 2x -59 -4 = 0

x² -2x -63 = 0

This is a quadratic equation when can be solved using factoring

Factors of 63 are
-63 = -7 x 9
-63 = 7 x -9

The second factorization 7 and -9 will also yield -2 when they are added

So

x² -2x -63 = 0

x² + 7x - 9x -63 = 0

x(x + 7) -9(x + 7) = 0

Factor out common term x + 7 to get

(x + 7)(x - 9) = 0

This means
x + 7 = 0 ==> x = -7
x - 9 = 0 ==> x = 9

The solutions are therefore x = 9 and x = -7

Therefore the number can be 9 or -7

User Luke Madhanga
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