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Need help please!! Estimate the percentage

Need help please!! Estimate the percentage-example-1
User Ramadhan
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1 Answer

7 votes

Answer:

Part a

First option
Increase from around $160,000 to around $245000 about a 53% increase

Part b
The prices increased from $220,000 to $245,000

Part c
The prices decreased from $245,000 to $215,000 . This is about a 12% decrease (actual value is 12.24%)

Explanation:

a. From the graph (or looking at the answer choices) we see that in 1999 the median housing price was $160,000

In 2007, we see that the median housing price was approx $245,000. We can eliminate the second and third choices since in 2007, the median price was definitely greater than $220,000


\% \;increase = (\$ \;increase )/(price \;in \;1999) * 100\\\\= (245,000 - 160,000)/(160,000) * 100\\\\= (85,000)/(160,000) * 100\\\\= 0.53125* 100\\\\= 53.125%\\\\\approx 53 \%

Hence the correct answer choice is the first option

Part b

From what I can see of the graph(kinda difficult) the median house price was $220,000 in 2004(the point being halfway between 210,000 and 230,000

The median price in 2007 from the information provided in Part a was $245,000

Increase in median price between 2004 and 2007 is 245,000 - 220,000 = $25,000

As a percentage relative to 2004 price this would be

25,000/220,000 x 100

= 11.36 % which I guess, if you rounded up would be 12%

So I am not a 100% sure on this but this is what I can read from the graph

Answer: The prices increased from $220,000 to $245,000

(c) Price for 2007 from part (a) $245,000

Price for 2009 from graph = $215,000
Price decrease = 215,000 - 245,000 = -30,000 (negative indicating a decrease)

Price decrease from 2007 to 2009 as a percentage of 2007 prices:
30,000/215,000 x 100 = 12.24 %which i guess you can round down to 12% or round up to 13% - again not sure.

Answer should be:
The prices decreased from $245,000 to $215,000 . This is about a 12% decrease

User Tammo Freese
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