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A gas at a pressure of 3.0 atm has a volume of 2L. Calculate the volume of this gas if the pressure is increased to 7 atm?

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Step-by-step explanation:

We can use Boyle's Law to solve this problem, which states that the product of the pressure and volume of a gas is constant at constant temperature. Mathematically, this can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Plugging in the given values, we get:

P1 = 3.0 atm

V1 = 2 L

P2 = 7 atm

V2 = ?

Using the formula P1V1 = P2V2, we can solve for V2:

V2 = (P1V1) / P2

V2 = (3.0 atm x 2 L) / 7 atm

V2 = 0.86 L (rounded to two decimal places)

Therefore, the volume of the gas at a pressure of 7.0 atm is 0.86 L.

User Mark Mikofski
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