Answer:
- Length: 22.5 in
- Width: 19.5 in
Explanation:
You want the dimensions of a rectangular painting with a perimeter of 84 inches and length 3 more inches than width.
Setup
We can write equations for the given relationships:
2(L +W) = 84 . . . . . . . . perimeter
L = W +3 . . . . . . . . . . . length
Solution
Substituting for L using the second equation, we have ...
2(W +3 +W) = 84
4W +6 = 84 . . . . . . . simplify
4W = 78 . . . . . . . . . subtract 6
W = 19.5 . . . . . . . . divide by 4
L = 19.5 +3 = 22.5 . . . . . find length
The dimensions of the painting are 19.5 inches wide by 22.5 inches long.
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