Question

How much heat is necessary to raise the temperature of 3g of water 22°C?

Answer 1

Answer:, it would require 277.992 Joules of heat to raise the temperature of 3g of water by 22°C.

Step-by-step explanation:

Q = m * c * ΔT

where Q is the amount of heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is approximately 4.184 J/(g°C).

Using this information, we can calculate the amount of heat required to raise the temperature of 3g of water by 22°C:

Q = 3g * 4.184 J/(g°C) * 22°C

Q = 277.992 J

Therefore, it would require 277.992 Joules of heat to raise the temperature of 3g of water by 22°C.

Answer 2

Step-by-step explanation:

The amount of heat needed to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is 4.184 J/g°C.

So, to find the heat energy required to raise the temperature of 3g of water by 22°C, we can plug in the values:

Q = (3g) x (4.184 J/g°C) x (22°C)

Q = 277.752 J

Therefore, it would take 277.752 J of heat energy to raise the temperature of 3g of water by 22°C.