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2x^2 + 7x + 6 = 0 double root real and rational roots real and irrational roots non-real roots

1 Answer

5 votes

Answer:

-3/2 & -2

Explanation:

2x²+7x+6=0

ax²+bx+c=0

where a=2

b=7

c=6

using factorisation method we say a×c then we find factors that when u manipulate it it equals coefficient b

so

2x²+7x+6=0

ac=2×6=12 factors of 12. (1, 12 )(2. ,6.) (3 4) (6 4)

factors are 3 and 4

2x² +4x+3x+6=0

2x(x+2)+3(x+2)=0

(2x+3)(x+2)=0

2x+3=0 & x+2=0

2x= -3 & x= -2

x= -3/2 and -2

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